Calling synchronize_irq() right before free_irq() is quite useless. On one
hand the IRQ can easily fire again before free_irq() is entered, on the
other hand free_irq() itself calls synchronize_irq() internally (in a race
condition free way), before any state associated with the IRQ is freed.
Link: https://lore.kernel.org/r/20220513081647.1631141-1-chi.minghao@zte.com.cn
Reported-by: Zeal Robot <zealci@zte.com.cn>
Signed-off-by: Minghao Chi <chi.minghao@zte.com.cn>
Acked-by: Michal KalderonĀ <michal.kalderon@marvell.com>
Signed-off-by: Jason Gunthorpe <jgg@nvidia.com>
if (dev->int_info.msix_cnt) {
idx = i * dev->num_hwfns + dev->affin_hwfn_idx;
vector = dev->int_info.msix[idx].vector;
- synchronize_irq(vector);
free_irq(vector, &dev->cnq_array[i]);
}
}