cfg80211: Fix parsed country IE info for 5 GHz
authorLuis R. Rodriguez <lrodriguez@atheros.com>
Thu, 8 Jan 2009 01:43:37 +0000 (17:43 -0800)
committerJohn W. Linville <linville@tuxdriver.com>
Fri, 16 Jan 2009 22:08:24 +0000 (17:08 -0500)
The country IE number of channels on 5 GHz specifies the number
of 5 GHz channels, not the number of sequential channel numbers.
For example, if in a country IEs if the first channel given is 36
and the number of channels passed is 4 then the individual channel
numbers defined for the 5 GHz PHY by these parameters

are: 36, 40, 44, 48
not: 36, 37, 38, 39

See: http://tinyurl.com/11d-clarification

Signed-off-by: Luis R. Rodriguez <lrodriguez@atheros.com>
Acked-by: Johannes Berg <johannes@sipsolutions.net>
Signed-off-by: John W. Linville <linville@tuxdriver.com>
net/wireless/reg.c

index 5f6d20d98eebd6b1e0533c02498e16cf35c6ce91..bc494cef21026e943215670b9899378fcdd900c3 100644 (file)
@@ -563,6 +563,7 @@ static struct ieee80211_regdomain *country_ie_2_rd(
 
        /* This time around we fill in the rd */
        while (country_ie_len >= 3) {
+               int end_channel = 0;
                struct ieee80211_country_ie_triplet *triplet =
                        (struct ieee80211_country_ie_triplet *) country_ie;
                struct ieee80211_reg_rule *reg_rule = NULL;
@@ -584,6 +585,23 @@ static struct ieee80211_regdomain *country_ie_2_rd(
 
                reg_rule->flags = flags;
 
+               /* 2 GHz */
+               if (triplet->chans.first_channel <= 14)
+                       end_channel = triplet->chans.first_channel +
+                               triplet->chans.num_channels;
+               else
+                       /*
+                        * 5 GHz -- For example in country IEs if the first
+                        * channel given is 36 and the number of channels is 4
+                        * then the individual channel numbers defined for the
+                        * 5 GHz PHY by these parameters are: 36, 40, 44, and 48
+                        * and not 36, 37, 38, 39.
+                        *
+                        * See: http://tinyurl.com/11d-clarification
+                        */
+                       end_channel =  triplet->chans.first_channel +
+                               (4 * (triplet->chans.num_channels - 1));
+
                /* The +10 is since the regulatory domain expects
                 * the actual band edge, not the center of freq for
                 * its start and end freqs, assuming 20 MHz bandwidth on
@@ -593,8 +611,7 @@ static struct ieee80211_regdomain *country_ie_2_rd(
                                triplet->chans.first_channel) - 10);
                freq_range->end_freq_khz =
                        MHZ_TO_KHZ(ieee80211_channel_to_frequency(
-                               triplet->chans.first_channel +
-                                       triplet->chans.num_channels) + 10);
+                               end_channel) + 10);
 
                /* Large arbitrary values, we intersect later */
                /* Increment this if we ever support >= 40 MHz channels